Question

Решите уравнение (3x-5)(2x+7)=(3x+1)(2x-3)+4x

Answer 1

(3x-5)(2x+7)=(3x+1)(2x-3)+4x
6$x^{2}$ +21x - 10x - 35 = 6$x^{2}$ - 9x + 2x - 3 + 4x
11x + 9x - 6x = 32
14x = 32
x = $frac{32}{14}$
x = $frac{16}{7}$
x = 2$frac{2}{7}$

Answer 2

6x^2 +21x - 10x -35 =6x^-9x+2x-3+4x,
14x=32, x=16/7