Question

(11x+5)(2x-3)+(12-8x) вынести общий множитель за скобки
(3a+1)(7a-2)-(6a+2)(8a+3)

Answer 1

$(11x+5)(2x-3)+(12-8x)=\= (11x+5)(2x-3)+((-4)*(-3)+(-4)*2x)=\= (11x+5)(2x-3)+(-4)*((-3)+2x)=\= (11x+5)*(2x-3)+(-4)*(2x-3)=\= (2x-3)*((11x+5)+(-4))=(2x-3)(11x+1)$
----------------------
$(3a+1)(7a-2)-(6a+2)(8a+3)=\= (3a+1)(7a-2)-(2*3a+2*1)(8a+3)=\= (3a+1)(7a-2)-2*(3a+1)(8a+3)=\= (3a+1)*(7a-2)-(3a+1)*(2*(8a+3))=\= (3a+1)*((7a-2)-(2*(8a+3)))=\= (3a+1)*(7a-2-2*(8a+3))=\= (3a+1)*(7a-2-16a-6)=(3a+1)*(-9a-7)=\= (3a+1)*((-1)*9a+(-1)*7)=\= (3a+1)*(-1)*(9a+7)=(-1)*(3a+1)*(9a+7)=\= -(3a+1)(9a+7)$