Question

Помогите пожалуйста!!! 4 номер!!!! Срочно!!!!

Answer 1

$sqrt{9-6 sqrt{2} }= sqrt{3(3-2 sqrt{2}) } = sqrt{3(2-2 sqrt{2}+1) } =$$sqrt{3}* sqrt{( sqrt{2} ) ^{2}-2 sqrt{2} +1 ^{2} }= sqrt{3} * sqrt{( sqrt{2}+1) ^{2} }= sqrt{3}*( sqrt{2}+1)= sqrt{6} +$$sqrt{3}$
2) $sqrt{27+10 sqrt{2} } = sqrt{25+10 sqrt{2}+2 } = sqrt{5 ^{2} +10 sqrt{2}+( sqrt{2}) ^{2} } = sqrt{(5+ sqrt{2}) ^{2} }$$=5+ sqrt{2}$