Question

(X-10)^2=(x+7)^2-17 помогите плиз очень надо

Answer 1

$(x-10)^2=(x+7)^2-17$
$(x+7)^2-(x-10)^2=17$
$(x+7-(x-10))(x+7+(x-10))=17$
$17(2x-3)=17$
$2x-3=1$
$2x=4$
$x=2$