Question

Даю 70 балов за решение

1) log2 (3x-2) > 2

2) log1/3 (5x-1) > -2

3) log7 (5x - 13) < log7 (2x + 5)

4) log1/3 (1 - 2x) > log1/3 (2x - 2)

5) log2/2 (x - 2) < 1

6) log2/3 x - 5log3 x > 6

Answer 1

1) $frac{log(3x-2)}{log(2)} textgreater 2$
x>2
(2;∞)
3) $frac{log(5x-13)}{log(7)} textgreater frac{log(2x+5)}{log(7)}$
    $log frac{(5x-13)}{(2x+5)} textless 0$
    $frac{13}{5} textless x textless 6$