Предмет: Алгебра, автор: andromeda31

Помогите с логарифмами!!!!!

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Ответы

Автор ответа: xtoto
0
log_2(4x+1) textless  log_2(2x+5)\
 4x+1 textless  2x+5 and x textgreater  -frac{1}{4} and x textgreater  -frac{5}{2}\
 2x textless  4 and x textgreater  -frac{1}{4}\
 x textless  2 and x textgreater  -frac{1}{4}\
 xin (-frac{1}{4}; 2)

log_{0.2}(x^2-x-2) textgreater  log_{0.2}(-x^2+2x+3)\
 x^2-x-2 textless  -x^2+2x+3 and x^2-x-2 textgreater  0 and -x^2+2x+3 textgreater  0\
 2x^2-3x-5 textless  0 and xin (-infty;-1)cup(2;+infty) and xin(-1;3)\
 2x^2+2x-5x-5 textless  0 and xin(2;3)\
 2x(x+1)-5(x+1) textless  0 and xin(2;3)\
(x+1)(2x-5) textless  0 and xin(2;3)\
  [x-(-1)]*[x-2.5] textless  0 and xin(2;3)\
 xin (-1; 2.5) and xin(2;3)\
xin(2;2.5)

log_{x-1}(9-x^2) textless  0\\
 left { {{log_{x-1}(9-x^2) textless  log_{x-1}(1)} atop {x-1 textgreater  0 and x-1 neq 1} and 9-x^2 textgreater  0} right.; \

 left { {{log_{x-1}(9-x^2) textless  log_{x-1}(1)} atop {0 textless  x-1 textless  1 and x^2-9 textless  0} right. or 
 left { {{log_{x-1}(9-x^2) textless  log_{x-1}(1)} atop {x-1 textgreater  1 and x^2-9 textless  0} right.;\

 left { {{9-x^2 textgreater  1} atop {1 textless  x textless  2 and (x-3)(x+3) textless  0} right. or 
 left { {{9-x^2 textless  1} atop {x textgreater  2 and (x-3)(x+3) textless  0} right.;\

 left { {{x^2-8 textless  0} atop {1 textless  x textless  2 and -3 textless  x textless  3} right. or 
 left { {{x^2-8 textgreater  0} atop {x textgreater  2 and -3 textless  x textless  3} right.;\

 left { {{(x-2 sqrt{2})(x+2 sqrt{2} )  textless  0} atop {1 textless  x textless  2} right. or 
 left { {{(x-2 sqrt{2})(x+2 sqrt{2} )  textgreater  0} atop {2 textless  x textless  3} right.;\

 left { {{-2 sqrt{2} textless  x textless  2 sqrt{2}} atop {1 textless  x textless  2} right. or 
 left { {{x textless  -2 sqrt{2} or x textgreater  2 sqrt{2}} atop {2 textless  x textless  3} right.;\

 left { {{xin (-2 sqrt{2}; 2sqrt{2})} atop {xin(1; 2)} right. or left { {{xin (-infty; -2 sqrt{2}) cup (2 sqrt{2}; +infty)} atop {xin(2; 3)} right.;\\ xin(1; 2)}  or xin(2 sqrt{2} ; 3)} right.;\\ xin(1; 2)} cup (2 sqrt{2} ; 3)} right..\

log_x(x^3-x^2-2x) textless  3\\
left { {{x^3-x^2-2x textgreater  x^3} atop {0 textless  x textless  1} and x^3-x^2-2x textgreater  0} right. or left { {{x^3-x^2-2x textless  x^3} atop {x textgreater  1 and x^3-x^2-2x textgreater  0}} right.;\\
left { {{2x^3-x^2-2x textgreater  0} atop {0 textless  x textless  1} and xin(-1;0)cup (2;+infty)} right. or left { {{x^2+2x textgreater  0} atop {x textgreater  1 and x(x-2)(x+1) textgreater  0}} right.;\

left { {{2x^3-x^2-2x textgreater  0} atop {xin{}} right. or left { {{x(x+2) textgreater  0} atop {x textgreater  1 and xin(-1;0)cup (2;+infty)}} right.;\\
xin{} or  left { {{xin(-infty;-2)cup (0;+infty)} atop {xin(2; +infty)}} right. \\
xin{} or xin(2; +infty)\\
xin(2; +infty)
Автор ответа: xtoto
0
сейчас последнее исправлю
Автор ответа: andromeda31
0
спасибо
Автор ответа: xtoto
0
и первое, обожди использовать мое решение
Автор ответа: xtoto
0
сейчас все ок
Автор ответа: m11m
0
!!!!!!!!!!l!!!!!!!!!!!!!!!!
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