Question

Пасаны, решите 5 плес

Answer 1

$5^{frac{6x+3}x}=sqrt[4]{125^{2x+1}}\sqrt[4]{125^{2x+1}}=left((5^3)^{2x+1}right)^{frac14}=left(5^{6x+3}right)^{frac14}=5^{frac{6x+3}4}\5^{frac{6x+3}x}=5^{frac{6x+3}4}\frac{6x+3}x=frac{6x+3}4\24x+12=6x^2+3x\6x^2-21x-12=0;;div3\2x^2-7x-4=0\D=49+4cdot3cdot4=49+32=81\x_{1,2}=frac{7pm9}4\x_1=-frac12\x_2=4$