Question

Найти y '(0), если y = (x ^ 2-1) / (e ^ x).

Answer 1

$y= frac{x^2-1}{e^{x}} \\y'= frac{2xcdot e^{x}-(x^2-1)cdot e^{x}}{e^{2x}} = frac{2x-x^2+1}{e^{x}}$

$y'(0)= frac{1}{e^0} =1$