Question

ПОМОГИТЕ СРОЧНО С АЛГЕЬРОЙ!!!!!!!tg(2Π-a)*cos (Π-a)/tg(3Π/2+a)*cos(3Π/2+a)

Answer 1

$frac{tg(2 pi - alpha )*Cos( pi - alpha )}{tg( frac{3 pi }{2} + alpha )*Cos( frac{3 pi }{2} + alpha) } = frac{-tg alpha *(-Cos alpha )}{-Ctg alpha *Sin alpha } =- frac{ frac{Sin alpha }{Cos alpha } *Cos alpha }{ frac{Cos alpha }{Sin alpha }*Sin alpha } =- frac{Sin alpha }{Cos alpha } =-tg alpha$