Question

Найти производную функции

Answer 1

$(-sin frac{e^{3x}}{1+e^{3x}} )'=-cos(e^{3x}}{1+e^{3x}} )*(e^{3x}}{1+e^{3x}} )'=\ =-cos(e^{3x}}{1+e^{3x}} )* frac{3e^{3x}(1+e^{3x})-3e^{3x}*e^{3x}}{(1+e^{3x})^2} =\ =-cos(e^{3x}}{1+e^{3x}} )* frac{3e^{3x}}{(1+e^{3x})^2}$