Question

сократить добь
(3+2√2)
⁻⁻⁻⁻⁻⁻⁻⁻⁻
(1+√2)

Answer 1

$frac{3+ 2sqrt{2} }{1+ sqrt{2} } = frac{(3+ 2sqrt{2})(1- sqrt{2}) }{1-2 } =\ =-(3+2 sqrt{2} -3 sqrt{2}-4 )=-(-1- sqrt{2} )=1+ sqrt{2}$