Question

решите пожалуйста #5

Answer 1

1) $sqrt{-3} , sqrt{-5 ^{2} }$
2) $sqrt[3]{27} + sqrt{0,49} = sqrt[3]{3 ^{3} }+ sqrt{0,7 ^{2} } =3+0,7=3,7$
3) $( sqrt{x-1}) ^{2}=6 ^{2}$            x ≥ 1
x - 1 = 36
x = 37
4)$sqrt{72n ^{8}m ^{6} }= sqrt{36*2*(n ^{4) ^{2} } *(m ^{3}) ^{2} }=-6 sqrt{2} n ^{4}m ^{3}$