Question

(3√2+ 1)^2 - 2√18
Очень срочно

Answer 1

$(3 sqrt{2}+1)^{2}-2 sqrt{18}= \ = (3 sqrt{2})^{2}+2*3 sqrt{2}+1^{2}-2 sqrt{9*2}= \ =9*2+6 sqrt{2}+1-2*3 sqrt{2}= 18+6 sqrt{2}+1-6 sqrt{2}=19$

Answer 2

$(3 sqrt{2}+1) ^{2} -2 sqrt{18} =( 3sqrt{2}) ^{2} +2*3 sqrt{2}*1+1 ^{2}-2 sqrt{9*2}= 18 + 6 sqrt{2}$$+1-6 sqrt{2} =19$