Question

16ab ^4
___________
-56a^3b^3


x^2-4x+4
__________
3x-6



(3a-3c)^2
_________
9c^2-9a^2




20+10a+5a^2
___________
a^3-8


СОКРАТИТЕ ДРОБЬ

Answer 1

$frac{16ab^2}{-56a^3b^3} = -frac{2}{7a^2b} \ \ frac{x^2-4x+4}{3x-6}= frac{(x-2)^2}{3(x-2)}= frac{x-2}{3}\ \ frac{(3a-3c)^2}{9c^2-9a^2}= frac{(3a-3c)^2}{(3c-3)(3c+3a)}= frac{(3c-3a)^2}{(3c-3a)(3c+3a)}= frac{3a-3c}{3a+3c}= frac{3(a-c)}{3(a+c)} = frac{a-c}{a+c}$