Предмет: Физика, автор: яИришка

Две одинаково однойменно заряженных шара ,расположены на расстоянии 0,9м одна от другой,взаимодействуют с силой 0,25н.Заряд второго шара равен +18нКл.Определите заряд первого шара.Вычислите ,какой будет сила електростатистического взаимодействия шаров после того,как они дотронутся один одного и опять разойдутся на такое самое расстояние?

Ответы

Автор ответа: ашот121121
0
Дано:
R = 0.9 м.
F = 0.25Н
q = 18 нКл = 18 * 10^-9 Клk = 9  * 10^9
q2 - ?
Закон Кулона:
F = kq1q2/R^2
Преобразовываем формулу:
FR^2 = kq1q2 = > q2 = FR^2/kq1 = -0.00125. = -1.25 мКл.
Прошу обратить внимание на минус, ибо в случае противоположного знака наши заряды банально бы отталкивались друг от друга
Автор ответа: Вика123458
0
Дано:R = 0.9 м.F = 0.25Нq = 18 нКл = 18 * 10^-9 Клk = 9  * 10^9q2 - ?Закон Кулона:F = kq1q2/R^2Преобразовываем формулу:FR^2 = kq1q2 = > q2 = FR^2/kq1 = -0.00125. = -1.25 мКл.Прошу обратить внимание на минус, ибо в случае противоположного знака наши заряды банально бы отталкивались друг от друга.
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