Question

1)x^2-x=0 2)p^2+15p=0

Answer 1

$x {}^{2} - x = 0 \ x times (x - 1) = 0 \ x = 0 \ x -1 = 0 \ x = 0 \ x = 1 \ x1 = 0. x2 = 1$
$p {}^{2} + 15p = 0 \ p times (p + 15) = 0 \ p = 0 \ p = - 15 \ p1 = - 15 .p2 = 0$