Question

x(x во 2степени +2+1)=2(x+1)

Answer 1

$x times ( {x}^{2} + 2 + 1) = 2(x + 1) \ x times ( {x}^{2} + 3) = 2x + 2 \ {x}^{3} + 3x = 2x + 2 \ {x}^{3} + 3x - 2x - 2 = 0 \ {x}^{3} + x - 2 = 0 \ {x}^{3} - x + 2x - 2 = 0 \ x times ( {x}^{2} - 1) + 2(x - 1) = 0 \ x times (x - 1) times (x + 1) + 2(x - 1) = 0 \ (x - 1) times (x times (x + 1) + 2) = 0 \ (x - 1) times ( {x}^{2} + x + 2 ) = 0 \ x - 1 = 0 \ {x}^{2} + x + 2 = 0 \ x = 1$