Question

помогите
1)(3$sqrt{6}$-2$sqrt{3}$)^2
2)($sqrt{14}$+$sqrt{3}$)($sqrt{3}$-$sqrt{14}$)

Answer 1

$(3 sqrt{6} -2 sqrt{3} )^2=54+12-12 sqrt{18} =66-36 sqrt{2} \ ( sqrt{14} + sqrt{3} )( sqrt{3} - sqrt{14} )=3-14=-11$