Question

сократить дробь:

12y^2-y-6/3y^2-5y+2

Answer 1

$12y^2-y-6=0;D=(-1)^2-4*12*(-6)=289=17^2$
$y_1=frac{1-17}{2*12}=-frac{2}{3}$
$y_2=frac{1+17}{2*12}=frac{3}{4}$

$frac{12y^2-y-6}{3y^2-5y+2}=\\ frac{12(x-frac{2}{3})(x-frac{3}{4})}{3(x-frac{2}{3})(x-1)}=\\ frac{4(x-frac{3}{4})}{x-1}=frac{4x-3}{x-1}$