Question

(3x²+2x-5)+(4x²-6x+12

Answer 1

$3x { }^{2} + 2x - 5 + 4x {}^{2} - 6x + 12 = 0$
$7x {}^{2} - 4x + 7 = 0$
D= 16-4*7*7
D<0
Решений нет