Question

sin квадрат x+sinxcosx=2cos квадрат x

Answer 1

$sin^2x-sinxcosx-2cos^2x | : cos^2x \x neq 0\ \tg^2x+tgx-2=0 \ t=tgx \ t_1 = -2 \ t_2 = 1 \ \x neq frac{pi}{2}\\ tg(x) = -2 \ x = arctg(-2) + pi n, n to Z \\ tg(x) = 1 \ x = frac{pi}{4} + pi n, n to Z$