Question

1)(2x-8)(3+7x)-7x(1+2x)=8
2)(1+6x)(3x-4)=2x(9x-7)
Решите уравнения

Answer 1

$1) 6x + 14 {x}^{2} - 24 - 56x - 7x - 14 {x}^{2} - 8 = 0 \ - 57x = 32 \ x = - frac{32}{57} \ \ 2)3x - 4 + 18 {x}^{2} - 24x - 18 {x}^{2} + 14x = 0 \ - 13x = 4 \ x = - frac{4}{13}$