Question

x^3+6x^2+3x-10=0 помогите решить уравнение...

Answer 1

$x^3+6x^2+3x-10=0 \ x^3-x^2+7x^2-7x+10x-10=0 \ x^2(x-1)+7x(x-1)+10(x-1) = 0 \ (x-1)(x^2+7x+10) = 0 \ (x-1)(x^2+5x+2x+10) = 0 \ (x-1)(x(x+5)+2(x+5))=0 \ (x-1)(x+2)(x+5) = 0 \ x_1 = 1 \ x_2 = -2 \ x_3 = -5$

Answer 2

$x {}^{3} + {6x}^{2} + 3x - 10 = 0 \ \ (x - 1)(x + 2)(x + 5) = 0$
х первое =1
х второе =-2
х третье =-5