Question

с-33 умножение многочленов

Answer 1

$(a+3)(b-7)=ab-7a+3b-21\(a-5)(11-b)=11a-ab-55+5b\(-8-a)(b+2)=-8b-16-ab-2a\(-7-b)(a-7)=-7a+49-ab+7b\\ (x-4)(x+8)=x^2+4x-32\(x-5)(9-x)=-x^2+14x-45\(3+x)(-1-x)=-x^2-4x-3\(x-10)(-x-6)=-x^2+4x+60\\(8+3x)(2y-1)=16y-8+6xy-3x\(2a-1)(3a+7)=6a^2+11a-7\(3a-2b)(2a-3b)=6a^2-13ab+6b^2\(15a+27)(-5a-9)=-75a^2-135a-135a-243=\=-75a^2-270a-243\\(3x^2-1)(2x+1)=6x^3+3x^2-3x-1\(3x^2-1)(2x^2+1)=6x^4+x^2-1\(m^2-n)(m+n^2)=m^3+m^2n^2-mn-n^3\(m^2-n)(m-n^2)=m^3-m^2n^2-mn+n^3\\(a+2)(a^2-a-3)=a^3+a^2-5a-6\(5b-1)(b^2-5b+1)=5b^3-25b^2+5b-b^2+5b-1=5b^3-\-26b^2+10b-1\(m-n+1)(m+n)=\=m^2+mn-mn-n^2+m+n=m^2-n^2+m+n\(m-2n)(m+2n-1)=m^2+2mn-m-2mn-4n^2+2n=\=m^2-m-4n^2+2n\\ 2(b+1)(b+3)=(2b+2)(b+3)=2b^2+8b+6\-8(y-1)(y+5)=(-8y+8)(y+5)=-8y^2-32y+40\b(3b+1)(2b-5)=(3b^2+b)(2b-5)=6b^3-13b^2-5b\5m(m-n)(m+3n)=(5m^2-5mn)(m+3n)=\=5m^3+10m^2n-15mn^2$