Question

Решить уравнение:
$(8x+3)^{2}$ - $x^{4}$ = 8$x^{2}$ + 16

Answer 1

$(8x+3)^{2} - x^{4} = 8 x^{2} + 16 \ (8x+3)^{2} = x^{4} + 8 x^{2} + 16 \ (8x+3)^{2} -( x^2 +4)^2=0 \ (8x+3 -( x^2 +4)) (8x+3 +( x^2 +4))=0 \ x^2-8x+1=0 \ D_1=16-1=15 \ x=4pm sqrt{15} \ x^2 +8x+7=0 \ D_1=16-7=9 \ x=-7 \ x=-1$
Ответ: $-1, -7, 4pm sqrt{15}$