Question

(2х+1х^2-3х - 2х-1х^2+3х) *х^-97х +1

Answer 1

$( frac{2x+1}{x^2-3x}- frac{2x-1}{x^2+3x})* frac{x^2-9}{7x}+1= frac{2x^3+6x^2+x^2+3x-2x^3+6x^2+x^2-3x}{(x^2-3x)(x^2+3x)}*$$frac{(x-3)(x+3)}{7x}+1= frac{14x^2(x-3)(x+3)}{x(x-3)x(+3)7x}+1= frac{2}{x}+1= frac{2+x}{x}$