Question

(a-3)(b+4)=
(X-7)(x+3)=
(2y+1)(5y-6)=

Answer 1

(a-3)(b+4)=ab+4a-3b-12
(x-7)(x+3)=
${x}^{2} + 3x - 7x - 21 = {x}^{2} - 4x - 21$
(2y+1)(5y-6)=
$10 {y}^{2} - 12y + 5y - 6 = 10 {y}^{2} - 7y - 6$