Question

(2tgп/6) /(1-tg^2п/6) =?

Answer 1

Воспользуемся формулой

$tg (2alpha)=frac{2tg alpha}{1-tg^2alpha}$

По ней

$frac{2tg (pi/6)}{1-tg^2(pi/6)}=tg(pi/3)=sqrt{3}$