Question

(x^2+2x-24)/(x^2-4x) при x=0.003

Answer 1

$dfrac{x^2+2x-24}{x^2-4x}= dfrac{x^2-4x+6x-24}{x(x-4)}= dfrac{x(x-4)+6(x-4)}{x(x-4)}= dfrac{x+6}{x}$

подставляем x
$dfrac{0,003+6}{0,003}= dfrac{0,003}{0,003}+ dfrac{6}{0,003}=1+ dfrac{6000}{3}=1+2000=2001$