Question

Plizzz pomagite
x2-2xy-y2=1    
x+y=2

Answer 1

$left { {{x^2-2xy-y^2=1} atop {x+y=2}} right. \ \ left { {{(x-y)^2-2y^2=1} atop {x+y=2}} right\ \ left { {{ (x-y-sqrt{2}y)(x-y+sqrt{2}y)=1} atop {x+y=2}} right. .\ \ left { {{(2-2y-sqrt{2}y)(2-2y+sqrt{2}y)=1} atop {x=2-y}} right.\ \ y_{1}=frac{sqrt{5}+sqrt{8}}{sqrt{2}}\ y_{2}=-frac{sqrt{5}-sqrt{8}}{sqrt{2}}\ x_{1}=frac{sqrt{5}}{sqrt{2}}\ x_{2}=-frac{sqrt{5}}{sqrt{2}}$