Предмет: Алгебра, автор: kamon1997

Plizzz pomagite
x2-2xy-y2=1    
x+y=2

Ответы

Автор ответа: Матов
0
 left { {{x^2-2xy-y^2=1} atop {x+y=2}} right. \
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 left { {{(x-y)^2-2y^2=1} atop {x+y=2}} right\
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 left { {{ (x-y-sqrt{2}y)(x-y+sqrt{2}y)=1} atop {x+y=2}} right. .\
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 left { {{(2-2y-sqrt{2}y)(2-2y+sqrt{2}y)=1} atop {x=2-y}} right.\
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 y_{1}=frac{sqrt{5}+sqrt{8}}{sqrt{2}}\
 y_{2}=-frac{sqrt{5}-sqrt{8}}{sqrt{2}}\
x_{1}=frac{sqrt{5}}{sqrt{2}}\
x_{2}=-frac{sqrt{5}}{sqrt{2}}\
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