Предмет: Химия, автор: Zjxtymjlbyrjbq

какой объём (н.у.) оксида углерода 4 образуется при сжигании 120 грамм углерода,содержащего 10% примесей

Ответы

Автор ответа: ChrisV3

C+O2=CO2
m(C)=120*0.9=108 г
n(C)=n(CO2)=108/44=2.(45)
V(CO2)=2.(45)*22.4=55 л

Ответ: 55 л

Автор ответа: 12Incubus

2C+O2=2CO2.
m(C)=120*0,1=12 г
n(CO2)=12/44=0,3 моль
V(CO2)=0.3*22.4=6.72 л

Автор ответа: 12Incubus

со всеми бывает) промахнулась)

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