Question

(x-3)^2 <5`/(x-3)
`/это корень

Answer 1

$(x-3)^2 textless 5 sqrt{x-3} \ (x-3)^2-5 sqrt{x-3} textless 0 \ sqrt{x-3}((x-3) sqrt{x-3}-5) textless 0 \ \ sqrt{x-3}((x-3) sqrt{x-3}-5)=0 \ \ sqrt{x-3}=0 \ x=3 \ \ (x-3) sqrt{x-3}-5=0 \ (x-3)^3=25 \ x-3= sqrt[3]{25} \ x= sqrt[3]{25}+3$

____+____(3)____-____(3+∛25)____+____

x∈(3; 3+∛25)