Question

Найдите числа х и у, удовлетворяющие равенству :

x^{2} + 5 y^{2} + 4xy + 2y + 1 = 0
$x^{2} + 5 y^{2} + 4xy + 2y + 1 = 0$

Answer 1

I hope this helps you

Answer 2

sorry, but you made a mistake, there is not 4y ^ 2, but 5 y ^ 2

Answer 3

no it's correct

Answer 4

there are two perfect square

Answer 5

4y^2+y^2=5y^2

Answer 6

I could, thanks again