Предмет: Геометрия,
автор: Данякеп
Всё на фото...............
Приложения:
Ответы
Автор ответа:
0
Ответы:
4. 36
5. 2
6. -16
4. 36
5. 2
6. -16
Приложения:
Автор ответа:
0
task/26548487
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4.
36√6tgπ/6*sinπ/4= 36√6* 1/√3*1/√2 =36√6* 1/√(3*2) =36√6* 1/√6 =36.
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5.
4√2cosπ/4*cos7π/3 =4√2*1/√2*cos(2π+π/3) =4cosπ/3= 4*1/2 =2
6.
8 / (sin(-27/4)*cos(31π/4) = 8 / (-(sin(27/4)*cos(31π/4) ) =
-8 / (sin(3*2π +3π/4)*cos(4*2π -π/4) )= - 8 / (sin(3π/4)*cosπ/4 ) =
-8 / (sin(π - π/4)*cosπ/4) = -8 / ( sin(π/4)*cos(π/4) ) =
-8 / ( (1/√2) * (1/√2) ) = -8 / (1/2) = -16 .
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...= -8 / (sinπ/4)*cosπ/4) = -16/ (2(sinπ/4)*cosπ/4) =
-16/sin(2*π/4) = -16/sin(π/2) = -16 /1 = -16.
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4.
36√6tgπ/6*sinπ/4= 36√6* 1/√3*1/√2 =36√6* 1/√(3*2) =36√6* 1/√6 =36.
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5.
4√2cosπ/4*cos7π/3 =4√2*1/√2*cos(2π+π/3) =4cosπ/3= 4*1/2 =2
6.
8 / (sin(-27/4)*cos(31π/4) = 8 / (-(sin(27/4)*cos(31π/4) ) =
-8 / (sin(3*2π +3π/4)*cos(4*2π -π/4) )= - 8 / (sin(3π/4)*cosπ/4 ) =
-8 / (sin(π - π/4)*cosπ/4) = -8 / ( sin(π/4)*cos(π/4) ) =
-8 / ( (1/√2) * (1/√2) ) = -8 / (1/2) = -16 .
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...= -8 / (sinπ/4)*cosπ/4) = -16/ (2(sinπ/4)*cosπ/4) =
-16/sin(2*π/4) = -16/sin(π/2) = -16 /1 = -16.
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