Question

log 1/4(2x-1) = log 1/4(x^2+x-3)

Answer 1

$2x - 1 = {x}^{2} + x - 3 \ 2x - 1 - {x}^{2} - x + 3 = 0 \ - {x}^{2} - x + 2 = 0 \ {x}^{2} + x - 2 = 0 \ x1 = 1 \ x2 = - 2$