Question

(3х-8)^2-(4х-6)^2+(5х-2)*(х+2)=24

Answer 1

$9 {x}^{2} - 48x + 64 - 16 {x}^{2} + 46x - 36 + 5x {}^{2} + 10x - 2x - 4 = 24 \ - 2x {}^{2} + 6x = 0 \ 2x( 3 - x) = 0 \ x(1) = 0 \ x(2) = 3$