Question

log4 (x+12)*logx 2=1

Answer 1

log4(x+12)*logx(2)=1(1/2)*log2(x+12) = logx(x) / logx(2)(1/2)*log2(x+12) = log2(x)  ОДЗ:x+12>0,x>-12,x не равен 1 и x>0 log2((x+12)^(1/2)) =  log2(x)(x+12)^(1/2)=x(x+12)=x^2x^2-x-12=0D=b^2-4*a*c  = 1-4*1*(-12) = 49x1= (1 + 7)/2 = 4x2= (1 - 7)/2 = -3