Question

Помо7ите решить по алгебре номер 741 (2,4)

Answer 1

#2

$left { {{0 textless 1-3x textless 1} atop {3-4x textless 2}} right.$

$left { {{x textgreater 0.25} atop {-1 textless -3x textless 0}} right.$

$left { {{x textgreater frac{1}{4} } atop {0 textless x textless frac{1}{3} }} right.$

x∈($frac{1}{4}$;$frac{1}{3}$)

#4


$left { {{3x-2 leq 5x-8} atop { frac{2x-1}{2-x} textless 4 }} right.$

$left { {{x geq 3} atop { frac{2x-1}{2-x} textgreater 4 }} right.$

$left { {{x geq 3} atop { frac{2x-1}{2-x}-4 textless 0 }} right.$

$left { {{x geq 3} atop { frac{2x-1-8+4x}{2x} textless 0 }} right.$

$left { {{x geq 3} atop { frac{6x-9}{2x} textless 0 }} right.$

Найдём нули

6x-9=0
2x=0

x=1.5
x=0

$left { {{x geq 3} atop {{1.5 textgreater x textgreater 0} }} right.$

x∈(1.5;3]