Question

Помогите решить!!!!!!!

Answer 1

a) $sqrt[4]{2002 ^{2} +2*2002*498+498 ^{2} } = sqrt[4]{(2002+498) ^{2} }= sqrt{2002+498} =$$sqrt{2500}=50$
б) $sqrt[3]{2001 ^{3} -3*2001 ^{2} *189+3+2001*189 ^{2}-189 ^{3} } = sqrt[3]{(2001-189) ^{3} } =$$2001-189= 1812$