Question

 Cократите  дробь   :

1)(x^4-16): (x+2)

2)

(27x^3-125): (9x^2-25)

Answer 1

$frac{x^4-16}{x+2} = frac{(x^2+4)(x+2)(x-2)}{x+2} =(x^2+4)(x+2) \ frac{27x^3-125}{9x^2-25} = frac{(3x-5)(9x^2+15x+25)}{(3x-5)(3x+5)} = frac{9x^2+15x+25}{3x+5}$