Question

Решите а б и в
Срочно все в приложении

Answer 1

$5^{2 sqrt{x} } + 5 textless 5^{ sqrt{x} +1 } +5^{ sqrt{x} } \ \ odz:x geq 0 \ \ (5^{ sqrt{x} })^2 +5 textless 5^{ sqrt{x} } * 5 +5^ sqrt{x} } \ \ t= 5^ sqrt{x} } \ \ t^2 +5 textless t*5+t \ \ t^2+5-6t textless 0 \ \ left(t-5right)left(t-1right) textless 0 \ t =1 ,5$

t∈(1;5)

$displaystyle 5^{ sqrt{x} } in (1;5) \ \ left { {{5^{ sqrt{x} } textgreater 1} atop {5^{ sqrt{x} } textless 5} right. \ \ 5^{ sqrt{x} } textgreater 1 \ 5^{ sqrt{x} } textgreater 5^0 \ sqrt{x} textgreater 0 \ sqrt{x} =0 \ x=0 \ xnotin mathbb{R} \ \ 5^{ sqrt{x} } textless 5 \ 5^{ sqrt{x} } textless 5^1 \ sqrt{x} textless 1 \ x textless 1 \ \ xin ( - infty ;0 ) cup ( 0 ; 1) \ \ x in(0,1)$

$displaystyle ( frac{1}{9} )^{|x-1|} textgreater ( frac{1}{27} )^{2x} \ \ 3^{-2*|x-1|} textgreater 3^{-6x} \ \ -2*|x-1| textgreater -6x \ \ -2*|x-1| +6x textgreater 0 \ \ -2(x-1)+6x textgreater 0 , x-1 geq 0\ -2x+2+6x textgreater 0 \ 4x+2 textgreater 0 \ 4x textgreater -2 \ x textgreater - frac{1}{2} , x geq 1 \ \ -2*(-(x-1))+6x textgreater 0 ,x-1 textless 0\ 2(x-1)+6x textgreater 0 \ 2x-2+6x textgreater 0 \ 8x-2 textgreater 0 \ 8x textgreater 2 \ x textgreater frac{1}{4} , x textless 1$
$displaystyle left { {{x textgreater - frac{1}{2},x geq 1} } atop {x textgreater frac{1}{4},x textless 1 }} right. \ \ left { {{xin[1,+infty)} atop {xin(1 frac{1}{4} ,1)}} right. \ \ xin( frac{1}{4} ,+infty)$