Question

помогите решить плиз )

Answer 1

$displaystyle 1) \ \ 1)frac{24}{(2 sqrt{3} )^2} = frac{24}{4*3} = frac{6}{3} =2 \ \ \ 2) frac{ sqrt{75} }{ sqrt{3} } = sqrt{75:3} = sqrt{25} =5 \ \ \ 3) sqrt{18} * sqrt{2} = sqrt{18*2} = sqrt{36} =6 \ \ \ 4) 3sqrt{15} *6 sqrt{15} = 3*15*6 = 270 \ \ \ \ 2 ) \ \ 1)x^2 = 25 \ x= pm 5 \ \ 2)x^2+4=0 \ \ xnotin mathbb{R} \ \ 3)y^2=0 \ y=0$