Question

Решите уравнение: 2^(8-х^2)=4^х

Answer 1

2^(8-x^2) = 4^x
2^(8-x^2)= 2^(2x)
8-x^2 = 2x
8-x^2 - 2x = 0
-x^2 - 2x +8 = 0
x^2 + 2x - 8 =0
D=4+32 = 36=6^2
x1=-2+6 / 2 = 2
x2=-2-6/2 = -4
Ответ : x1=2 , x2 = -4