Question

помогите решить номер 2

Answer 1

$4^{2x} - 5cdot 4^{x} + 4 textless 0$
Замена:$4^x = y$
$y^2 - 5cdot y + 4 textless 0 \ \ D = 25 - 16 = 9 \ \ y_{12} = frac{5pm sqrt{9}}{2} = frac{5pm 3}{2} = left { {{4} atop {1}} right. \ \(y-4)(y-1) textless 0 \ \ yin(1;4) \ \ xin(0;1)$