Question

Z1+Z2, Z1-Z2, Z1*Z2, Z1/Z2. Если Z1=2-3i, Z2=4+3i

Answer 1

z₁=2-3i, z₂=4+3i

z₁+z₂=2-3i+4+3i=6

z₁-z₂=2-3i-(4+3i)=2-3i-4-3i=-2-6i

z₁*z₂=(2-3i)(4+3i)=8+6i-12i-9i²=8-6i+9=17-6i

z₁/z₂=(2-3i)/(4+3i)=(2-3i)(4-3i)/(4+3i)(4-3i)=(8-6i-12i+9i²)/(16-12i+12i-9i²)=(8-18i-9)/(16+9)=(-1-18i)/25