Question

Помогите решить 3 номер

Answer 1

$64x + x ^{-1} = - 16$
$64x + frac{1}{x} + 16 = 0$            $x neq 0$
$64 x^{2} + 16x + 1 = 0$
D = 16² - 4 * 1 + 64 = 256 - 256 = 0
$X = - frac{16}{128}= - 0,125$