Question

log корень из7(х+1)=4

Answer 1

$log _{ sqrt{7} } (x+1) = 4$                        ОДЗ: x + 1 > 0
$x + 1 = ( sqrt{7} ) ^{4}$                                     x > - 1
$x + 1 = 49$
$x = 48$