Question

Помогите!!!!!!!!!!!!!!!!!!!!

Answer 1

{2x-y=-1     ⇔ 2x=-1+y  ⇔ x = (y-1)/2  ⇔ x=1/2   *(y-1)  ⇔ x=0.5(y-1)
{y²-4x-2 = 0
y² - 4*0.5(y-1)  - 2 = 0
y² -  2(y-1) - 2 = 0
y² - 2y + 2 - 2 = 0
y² - 2y = 0
y(y-2) = 0
y₁ = 0
y-2=0
y₂ = 2
x₁= 0.5(0-1)=0,5*(-1)
x₁ = -0,5
x₂ = 0.5 (2-1) = 0,5*1
x₂ = 0.5   

Ответ: (-0,5 ;0) , (0,5 ; 2)