Question

Решите неравенство
2(x–3)^2+(x–3)√x > x

Answer 1

$mathtt{2(x-3)^2+(x-3)sqrt{x} textgreater 0;~(x-3)(2x+sqrt{x}-6) textgreater 0;~}\\mathtt{(x-3)(sqrt{x}-1,5) textgreater 0~to~xin[0;frac{9}{4})U(3;+infty)}$