Question

Найдите arcsin(sin$frac{92}{5} pi$)? С объяснением пжл

Answer 1

Найдем сначала sin(99π/5)=sin((100π/5)-(π/5))=
=sin(20π-(π/5))=sin(-π/5)
По формуле имеем arcsin(sina)=a, при -(π/2)arcsin(sin(99π/5))=arcsin(sin(-π/5))=
= -π/5